Please answer my question with solution or via picture if possible.
pg.394
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option b) 6√3 is correct.
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saadyasinkhan:
Thank you so much Sir
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See image attached.
Angle between R₁ and R₂ is 60°
Vector product is also called cross product.
Magnitude of cross product of R₁ and R₂ is |R₁||R₂| sinθ
(where θ is angle between the vectors)
So,
Magnitude of cross product = (3 cm) × (4 cm) × sin60 = 6√3 cm²
(b) is the correct option.
Angle between R₁ and R₂ is 60°
Vector product is also called cross product.
Magnitude of cross product of R₁ and R₂ is |R₁||R₂| sinθ
(where θ is angle between the vectors)
So,
Magnitude of cross product = (3 cm) × (4 cm) × sin60 = 6√3 cm²
(b) is the correct option.
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