please answer my questions
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Step-by-step explanation:
(I) ATQ
πr^2h=4/3πr^3
h=4/3r
csa of cylinder =2πrh
=2πr*4/3r
=8πr^2/3
csa of sphere=4πr^2
csa of cylinder/csa of sphere
=(8πr^2/3)/4πr^2
=2/3
b) 2:3
(II)let the dimensions of cuboid be 3k, 4k, 6k
volume =lbh
576=3k*4k*6k
576=72k^3
576/72=k^3
8=k^3
k=2
3k=6
4k=8
6k=12
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