Math, asked by ashimas0130, 10 months ago

please answer my questions​

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Answers

Answered by wwwmanthan272005
0

Step-by-step explanation:

(I) ATQ

πr^2h=4/3πr^3

h=4/3r

csa of cylinder =2πrh

=2πr*4/3r

=8πr^2/3

csa of sphere=4πr^2

csa of cylinder/csa of sphere

=(8πr^2/3)/4πr^2

=2/3

b) 2:3

(II)let the dimensions of cuboid be 3k, 4k, 6k

volume =lbh

576=3k*4k*6k

576=72k^3

576/72=k^3

8=k^3

k=2

3k=6

4k=8

6k=12

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