Question

please answer my questions​

Answer 1

Answer:

i) A. B = 2 + 1 - 3 = 0

ii) A × B = -4i + 5j - 1k

iii) Component of A in the direction of B = A(A.B) / lAl^2

= i + j + k (0)/ 3 = 0

iv) Unit vector perpendicular to A and B = A× B/ lAl lBl

= $- 4i + 5j - 1k \div \sqrt{3} \sqrt{14}$

$- 4i + 5j + - 1k \div \sqrt{42}$

Note - A &B are vectors, vector symbols are not mentioned due to technical difficulties.

hope this will help you

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