Question

please answer my questions

Answer 1

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Answer 2

✍✍HERE IS YOUR ANSWER..⬇⬇
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$\underline{SOLUTION}$ ➡

$\frac{6y - 3}{3y + 2} = 3 \\ \\ = > 6y - 3 = 3(3y + 2) \\ \\ = > 6y - 3 = 9y + 6 \\ \\ = >6 y - 9y = 6 + 3 \\ \\ = > - 3y = 9 \\ \\ = > y = \frac{9}{ - 3} \\ \\ = > y = - 3$

$\underline{Verification : -}$


$y = - 3$


$Putting \: \: the \: value \: \: of \: \: y \: \: in \: L.H.S. \: \: of \: \: \\ the \: equation, \: \: we \: \: get, \\ \\ L.H.S. = \frac{6y - 3}{3y + 2} \\ \\ = \frac{6 \times ( - 3) - 3}{3 \times ( - 3) + 2} \\ \\ = \frac{ - 18 - 3}{ - 9 + 2} \\ \\ = \frac{ - 21}{ - 7} \\ \\ = 3 \\ \\ = R.H.S.$

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