please answer my questions
Attachments:
Answers
Answered by
7
Answer:
Step-by-step explanation:
To Find:-
Height of the Tower = ?
Width of the River = ?
Find;
Let "x" be the Width of the River.
& "h" be the Height of the Tower.
In ∆ ABC,
Tan 61° = AB/ BC
=> 1.8 = h/X
=> H = 1.8 * x_________(1).
Now,
In ∆ ABD,
Tan 35° = AB/BD
=> 0.7 = h / (50+X)
=> h = 0.7 × (50+X)_________(2).
Equating eq(1) & (2). We get,
1.8 * X = 0.7 × (50+X)
=> 1.8 * X / 0.7 = 50 + X
=> 2.5x = 50 + X
=> 1.5x = 50
=> X = 50/1.5 = 33.33m.
Putting X = 33.33 in eq(1).
H = 1.8 * 33.33
=> H = 60m.
Hence,
Height of Tower is 60m.
& Width of River is 33.33m.
Step-by-step explanation:
To Find:-
Height of the Tower = ?
Width of the River = ?
Find;
Let "x" be the Width of the River.
& "h" be the Height of the Tower.
In ∆ ABC,
Tan 61° = AB/ BC
=> 1.8 = h/X
=> H = 1.8 * x_________(1).
Now,
In ∆ ABD,
Tan 35° = AB/BD
=> 0.7 = h / (50+X)
=> h = 0.7 × (50+X)_________(2).
Equating eq(1) & (2). We get,
1.8 * X = 0.7 × (50+X)
=> 1.8 * X / 0.7 = 50 + X
=> 2.5x = 50 + X
=> 1.5x = 50
=> X = 50/1.5 = 33.33m.
Putting X = 33.33 in eq(1).
H = 1.8 * 33.33
=> H = 60m.
Hence,
Height of Tower is 60m.
& Width of River is 33.33m.
Attachments:
Similar questions