please answer my questions genius question no 20?
Attachments:
Answers
Answered by
3
sorry but I know that's type
Attachments:
komalsingrajput:
it's wrong
sorry
are u from rbse board
cbse
hm
from where
Chandigarh
you give me 10.paper
I ask questions
Answered by
6
⛦Hᴇʀᴇ Is Yoᴜʀ Aɴsᴡᴇʀ⚑
▬▬▬▬▬▬▬▬▬▬▬▬☟
➧ Let the radius of the inscribed circle be r.
➧ The area of this circle
➾ Πr² = 154 (given)
➧ That is 22/7 x r² = 154
➧ Implies r² = 154 x 7/22
➾ 49
r = √49 = 7 cm.
➧ Let altitude AD = h
➧ Therefore,
➾ ADB = 900 & OD = 1/3
➾ AD i.e. r = h / 3
Implies,
➾ h = 3r = 3 x 7
➾ 21 cm
➧ Let each side of the triangle be a, then
➧ In right triangle ADB, AB² = AD² + BD²
➾ Implies, a² = h² + (a/2)²
➾ Implies, 4 a² = 4 h² + a²
➾ Implies, 3 a² = 4h²
➾ Implies, a = 2h / √3
➾ Implies, a = 2 / √3 x 21 = 2 / √3 x 21 x √3 / √3
➾ 14 x √3 cm
➧ Therefore, Perimeter of the triangle
➾ 3a = 3 x 14 √3
➾ 42√3
➾ 42 x 1.73
➾ 72.7 cm ...✔
_________
Thanks...✊
▬▬▬▬▬▬▬▬▬▬▬▬☟
➧ Let the radius of the inscribed circle be r.
➧ The area of this circle
➾ Πr² = 154 (given)
➧ That is 22/7 x r² = 154
➧ Implies r² = 154 x 7/22
➾ 49
r = √49 = 7 cm.
➧ Let altitude AD = h
➧ Therefore,
➾ ADB = 900 & OD = 1/3
➾ AD i.e. r = h / 3
Implies,
➾ h = 3r = 3 x 7
➾ 21 cm
➧ Let each side of the triangle be a, then
➧ In right triangle ADB, AB² = AD² + BD²
➾ Implies, a² = h² + (a/2)²
➾ Implies, 4 a² = 4 h² + a²
➾ Implies, 3 a² = 4h²
➾ Implies, a = 2h / √3
➾ Implies, a = 2 / √3 x 21 = 2 / √3 x 21 x √3 / √3
➾ 14 x √3 cm
➧ Therefore, Perimeter of the triangle
➾ 3a = 3 x 14 √3
➾ 42√3
➾ 42 x 1.73
➾ 72.7 cm ...✔
_________
Thanks...✊
Similar questions