Question

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Answer 1

Answer:

Answer of this ques is 32 and 48 the sum of 2 consecutive multiple of 6 is 66.

2 Let the number required is x

According to the question we can write as

(4/5)x−10=(2/3)x

On rearranging,](4/5)x−(2/3)x=10

Now taking the L.C.M of 3 and 5 is 15

(12x−10x)/15=10

On cross multiplication,

2x=150

x=150/2=75

So the required number is 75

3 . Answer: The number that should be added to each term of 7:13 to make it 2:3 is 5

4. -75×3 = 225

412 - 225 =187