Question

please answer my questions guy I will mark u brainliest please send me the details ​

Answer 1

1. 1268q+2

2. 55555\3

3. 1574

4. -35

please mark as brainlist

Step-by-step explanation:

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Answer 2

$\bold{\boxed {Question}}$

1) Find q if 1q56 and 1268q are divisible by 9

2) Write four 5 digit numbers divisible by 9

3) what should be subtracted from $_\frac{3}{7}$ to get $_\frac{1}{3}$

${\boxed{\boxed{\pink{\underline{\green{\mathscr {Solution}}} }} }}}$

1) We know that divisibility rule of 9 is that it's sum of numbers must divisible by 9 . So in this question the sum of given two number are 1+q+5+6=12+q and 1+2+6+8+q=17+q ,so in first sum i.e. 12+q the next number that is divisible by 9 is 18 so 12+q must be equal to 18 . So we can form a linear equation :-

12+q=18

==>q=18-12

$\bold{\boxed {===>q=6}}$

and in another sum that is 17+q the other number divisible by it is 18 :-

17+q=18

$\bold{\boxed {q=1}}$

So q are 6 and 1 respectively

2) We know that divisibility rule of 3 is that sum of it's number must be divisible 3 .So in this question we have to write 4 five digit number such that their sum is divisible by 9 .So the number can be

1)43212(4+3+2+1+2=12 which is divisible by 3)

2)12349

3)94231

4)24931

5)99651

3)Let the number be "$_x$"

A.T.Q

$\frac{3}{7}-x=\frac{1}{3} \\\\-x=\frac{1}{3}-\frac{3}{7} \\\\\-x=\frac{7-9}{21} \\\\-x=-\frac{2}{21} \\\\x=\frac{2}{21}$

So $_\frac{2}{21}$ must be subtracted

4) Given linear equation:-

$7X-5=15\\\\7X=15+5\\\\7X=20\\\\X=\frac{20}{7}$

So $X=\frac{20}{7}$

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