Question

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PS is a bisector of angle QPR in triangle PQR, PM perpendicular to QR. find angle MPS​

Answer 1

Step-by-step explanation:

In triangle PQR

angle P + angle Q + angle R =180°

angle P + 50° + 30°=180°

angle P = 100°

PS is the bisector of angle P.

angle QPS = angle SPR = 50°

In triangle PMQ

angle MPQ + angle PMQ + angle PQM = 180°

angle MPQ + 90 + 50 = 180

angle MPQ = 40°

angle QPS - angle MPQ = x°

50 - 40 = x

10° = x

Hence, x = 10°