Question

please answer my questions...✨✨✨
thanks ✨
good morning ✨✨✨​

Answer 1

Explanation:

1. f = l× d

f = 150×25

f = 3750

2. n = 18

p = 2

f = 36kgf

f = n×p

36 = 18×2

36 = 36

1

3. number I dont know

Answer 2

Answer:

A. Mechanical Advantage, MA=  Load arm/ Effort arm

​ As given, Load arm=25 cm

Effort arm=150−25=125 cm

MA= 125 Divided By 25 = 5 cm

B.Distance of nut from fulcrum (d) = 2 cm

Distance of effort from fulcrum (D) = 18 cm

Load × Load arm = Effort × Effort arm

Load × 2 cm = 36 kgf × 18 cm

Load = 324 kgf

C.Given: L = 5 kgf, Load arm = 20 cm, Effort arm = 100 – 20 = 80 cm.

(Since the crow bar is the lever of first order with fulcrum in between the load and the effort).

(i) Mechanical advantage = Effort arm/Load arm = 80/20 = 4

(ii) M.A. = Load(L)/Effort(E)

∴  Effort  = Load(L)/M.A.  = 5/4

= 1.25 kgf.