please answer my two questions
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cuboid=3*3*5 [i.e l*b*h]
LCM of 3,5=15
i.e 15cm is the dimension of the final cube.
therefore cuboid required across length=15/3=5
similarly, across breadth=15/3=5
similarly, across height=15/5=3
Therefore total no of cube is 75!
2-----
Area of square field = 5184m^2
Square root of 5184 = 72m
Therefore perimeter of square field = 4 * 72 = 288m
Rectangular field.
Breadth = x
Length = 2x
Perimeter = 2*length + 2*breadth
= 2(2x) + 2(x)
= 6x
Perimeter of rect field = Perimeter of square field.
6x = 288m
x = 48m
Breadth of rectangular field = 48m
Length of rectangular field = 96m.
Hope this helps.
LCM of 3,5=15
i.e 15cm is the dimension of the final cube.
therefore cuboid required across length=15/3=5
similarly, across breadth=15/3=5
similarly, across height=15/5=3
Therefore total no of cube is 75!
2-----
Area of square field = 5184m^2
Square root of 5184 = 72m
Therefore perimeter of square field = 4 * 72 = 288m
Rectangular field.
Breadth = x
Length = 2x
Perimeter = 2*length + 2*breadth
= 2(2x) + 2(x)
= 6x
Perimeter of rect field = Perimeter of square field.
6x = 288m
x = 48m
Breadth of rectangular field = 48m
Length of rectangular field = 96m.
Hope this helps.
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