Question

Please answer. Neatly and with explanation. No spammers allowed​

Answer 1

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Step-by-step explanation:

∠a = 180° ‐(70° + 44°) [ASP of Triangle]

∠a = 180 - (114°)

• ∠a = 66°

∠b = 180° - (110° + ∠2) [ASP of Triangle]

∠b = 180° - ( 110° + 36°)

∠b = 180° - 146)

• ∠b= 34°

• ∠c = 44°[opposite angles of a parallelogram are equal]

• ∠WXY = 80°[opposite angles of a parallelogram are equal]

[ Please observe the 2 figures that I have given ]

Answer 2

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✪QUESTION✪:-

• ∠WOZ = 110°
• ∠WZO = 36°
• ∠OZY = 44°

✪TO FIND✪:-

• ∠WXY
• ∠a
• ∠b
• ∠c

✪ANSWER✪:-

➥ ∠c:-

➠As the

• ∠WXO and ∠OZY
• ∠OXY and ∠WZO
• ∠WOZ and ∠XOY

are vertically opposite angles ,

• (1) ∠WXO = ∠OZY = ∠c = 44°
• (2) ∠OXY = ∠WZO = 36°
• (3) ∠WOZ = ∠XOY = 110°

➥∠WXY:-

➠∠WXY = ∠WXO + ∠OXY

➠∠WXY = 44° + 36° ( from (1) and (2) )

➠∠WXY = 80°

➥∠b:-

∆XOY

➠sum of the angles of a triangle = 180°

➠ ∠OXY + ∠XOY + ∠XYO = 180°

➠ 36° + 110° + ∠b = 180° ( from (2) and (3) )

➠146° + ∠b = 180°

➠∠b = 180° - 146°

➠∠b = 34°

➥∠a:-

➠as the

• ∠b and ∠OWZ

are vertically opposite angles,

• (4) ∠b = ∠OWZ = 34°

∆WZY

➠sum of the angles of a triangle = 180°

➠∠OWZ + ∠WZY + ∠ZYO = 180°

➠∠OWZ+ ∠WZO + ∠OZY + ∠ZYO= 180°

➠34° + 36° + 44° + ∠a = 180°

➠114° + ∠a = 180°

➠∠a = 180° - 114°

➠∠a = 66°

Hence

• ∠WXY = 80°
• ∠a = 66°
• ∠b = 34°
• ∠c = 44°