Math, asked by jyotirmayee7070, 9 months ago

Please answer no (ii) and (iii)

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Answers

Answered by Anonymous
2

Answer:

(56+55)(56-55)      [ a^2-b^2=(a+b)(a-b)]

= 111*1

= 111

(82+81)(82-81)

= 163*1

= 163

Answered by uddipta2580
2

Answer:

i.111

ii.163

Step-by-step explanation:

used formula = (a^2-b^2)=(a+b)(a-b)

i. 56^2-55^2=(55+56)(56-55)=111×1=111

ii.82^2-81^2=(82+81)(82-81)=163×1=163

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