Question

Please answer- one of the zeroes of polynomial 2x^2+7x-4,

Answer 1

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Answer 2

Solution :-

$2 {x}^{2} + 7x - 4 \\ by \: \: factorisation \: \: method \\ 2 {x}^{2} + 8x - x - 4 = 0 \\ (2 {x}^{2} + 8x)( - x - 4) = 0 \\ 2x(x + 4) - 1(x + 4) \\ (2x - 1)(x + 4) = 0 \\ 2x - 1 = 0 \: \: \: \: or \: \: \: \: x + 4 = 0 \\ 2x = 1 \: \: \: \: or \: \: \: \: x = - 4 \\ x = \frac{1}{2} \: \: \: \: or \: \: \: \: x = - 4$

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