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Let speed of the boat in still water = x km/hr, and Speed of the current = y km/hr Downstream speed = (x + y) km/hr Upstream speed = (x − y) km/hr Let 1 x + y 1x+y = u and 1 x − y 1x−y = v Put in the above equation we get, 24u + 16v = 6 Or, 12u + 8v = 3 ... (3) 36u + 12v = 6 Or, 6u + 2v = 1 ... (4) Multiplying (4) by 4, we get, 24u + 8v = 4v … (5) Subtracting (3) by (5), we get, 12u = 1 ⇒ u = 1 12 112 Putting the value of u in (4), we get, v = 1 4 14 ⇒ 1 x + y 1x+y = 1 12 112 and 1 x − y 1x−y = 1 4 14 ⇒ x + y = 12 and x − y = 4 Thus, speed of the boat in still water = 8 km/hr, Speed of the current = 4 km/hrRead more on Sarthaks.com - https://www.sarthaks.com/972083/motorboat-covers-distance-16km-upstream-24km-downstream-hours-covers-distance-upstream
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