Question

please answer

only first part​

Answer 1

Answer:

Step-by-step explanation:

$sin\dfrac{5\pi}{3} \\\\=sin(2\pi-\dfrac{\pi}{3})\\\\=sin\dfrac{\pi}{3}\\\\=\dfrac{\sqrt{3} }{2}$

(∵ sin ( π - θ ) = sinθ )