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Step-by-step explanation:
1 - cosB = (2/5) → cosB = (2/5) - 1
→ cosB = (3/5) = base/hypo.
Let, base be 3a and hypotenuse be 5a, using pythagoras theorem,
→ height² = (5a)² - (3a)² = 25a² - 9a²
→ height² = 16a² → height = 4a
Therefore, sinB = 4a/5a = 4/5
Solving LHS:
→ 25sinB(sinB - cosB)
→ 25(sin²B - sinB.cosB)
→ 25{(4/5)² - (3/5)(4/5)}
→ 25{ 16/25 - 12/25}
→ 25(16 - 12)/25
→ 25(4)/25
→ 4
Proved.
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