Question

please answer only if you know



6x²+3x-33=0​

Answer 1

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$\red \rule{300}{2.5}$

$\bold{\huge{ \tt{ \color{yellow}{Answer:}}}} \\ \bm{ \implies6x^2+3x - 33 = 0 } \\ \bm{ \implies \: 6x ^{2} -9x+22x - 33 = 0} \\ \bm{ \implies \: 3x(2x-3)+11(2x-3)=0} \\ \bm{\implies(3x+11)(2x-3)=0} \\ \bm{\implies3x+11=\frac{\cancel0}{(\cancel{2x-3)}}} \\ \bm{ \implies3x+11=0}</p><p> \\ \bm{\implies3x=-11} \\ \bm{\implies\fbox{ x=-\frac{11}{3}}} \\ \bm{And \: also} \\ \bm{\implies2x-3= \frac{0}{(3x+11)} } \\ \bm{\implies\boxed{x= \frac{3}{2} }}$

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Note:There is two Values of x.

$\rule{300}{2}$

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