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3
Answer:
The given circuit can be simplified as follows
R=3+
10+3+R
10×(3+R)
=3+
13+R
30+10R
R=
13+R
39+3R+30+10R
=
13+R
69+13R
13R+R ^2
=69+13R⇒R=
√69ohm
there option c is correct √69ohm
Explanation:
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