Question

please answer ONLY IF YOU KNOWW!

Answer 1

Answer:

4^3to4^-5;5^5to5^-5 is answer I think so as 4 is even number as 2and 5is odd as 3 so they will have the same formula

Answer 2

Answer:

${6}^{ - 1}$

Step-by-step explanation:

${3}^{3} \: to \: {3}^{ - 3} \\ {3}^{3} \times {3}^{ - 3}$

${a}^{m} \times {a}^{n} = {a}^{m + n }$

${3}^{3 - 3} \\ {3}^{1}$

${2}^{3} \: to \: {2}^{ - 4} \\ {2}^{3} \times {2}^{ - 4} \\ \: {a}^{m} \times {a}^{n} = {a}^{m + n} \\ {2}^{3 - 4} \\ {2}^{ - 1}$

${3}^{1} \: and \: {2}^{ - 1} \\ {3}^{1} \times {2}^{ - 1}$

Using,

${a}^{m} \times {b}^{m} = ({ab})^{m}$

${3}^{1} \times {2}^{ - 1} \\ ( {3 \times 2 )}^{ - 1} \\ {6}^{ - 1}$