Please answer part= h to i
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Answer:
h)4a²b-(a²-b)²
=4a²b-(a^4-2a²b+b²)
=4a²b-a^4+2a²b-b²
=-a^4-b²+4a²b+2a²b
=-a^4-b²+6a²b
=a^4+b²-6a²b
i)(xy+3z)²-(xy-3z)(xy-3z)
=(xy+3z)²-(xy-3z)²
=(x²y²+6xyz+3z²)-(x²y²-6xyz+9z²)
=x²y²+6xyz+3z²-x²y²+6xyz-9z²
=x²y²-x²y²+6xyz+6xyz+3z²-9z²
=12xyz-6z²
=6z(2xy-z)
j)[(a+1)(a-1)](a²+1)
=[(a)²-(1)²](a²+1)
=(a²-1)(a²+1)
=(a²)²-(1)²
=a^4-1
k)[(x²-y²)(x²+y²)](x^4+y^4)
=[(x²)²-(y²)²](x^4+y^4)
=(x^4-y^4)(x^4+y^4)
=(x^4)²+(y^4)²
=x^8+y^8
l)(x-1)(x+1)(x²+1)(x^4+1)(x^8+1)
=[(x)²-(1)²](x²+1)(x^4+1)(x^8+1)
=[(x²-1)(x²+1)](x^4+1)(x^8+1)
=[(x²)²-(1)²](x^4+1)(x^8+1)
=[(x^4-1)(x^4+1)](x^8+1)
=[(x^4)²-(1)²](x^8+1)
=[(x^8-1)(x^8+1)]
=[(x^8)²-(1)²]
=(x^16-1)
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