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Answer:
60 Ω
Explanation:
We know that, in a parallel circuit, the voltage across each resistor is the same.
Voltage across 20Ω, V=I2×R2
=20×0.3
=6 V
Current across 15Ω, I2=V/R2
=6/15
=0.4 A
Applying Kirchhoff's junction rule,
I1+I2+I3=IA
I1+0.3+0.4=0.8
∴I1=0.1 A
∴Resistance R1=V/I1
=6/0.1
=60 Ω
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