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since I 1 = 3A so voltage across this wire will be current × resistance
since in this wire resistance = 20 ohm
so voltage across this is = 3× 20= 60 volt
since all the resistance are in parallel connection
therefore voltage across them will be same
therefore V1=V2=V3
therefore i3 = V3/R3=60/60= 1 A
and i1= V1/R1= 60/10 = 6 A
and voltage of battery will be 60 volt
since in this wire resistance = 20 ohm
so voltage across this is = 3× 20= 60 volt
since all the resistance are in parallel connection
therefore voltage across them will be same
therefore V1=V2=V3
therefore i3 = V3/R3=60/60= 1 A
and i1= V1/R1= 60/10 = 6 A
and voltage of battery will be 60 volt
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