Question

please answer please can anybody​

Answer 1

Hey mate
here is your answer :--

Given :- distance of object (u) = -30cm
focal length = 60 cm

solution :- 1/f = 1/v - 1/u

1/ 60 = 1/v - 1/ -30
1/60 + 1/-30 = 1/v
1/60 + -2/ 60 = 1/v
1+(-2)/60 = 1/v
-1/60 = 1/v
v = -60 cm

now,

h2/h1 = v/u
9/h1 = -60/-30
h1 = -60×9/-30
h1= 18cm

So,
Position of the image = -60cm
Length of the image = 18 cm
Nature = Real and inverted

Hope this help you mate

Answer 2

Answer:

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