Question

please answer please

content quality

Answer 1

Answer:

Step-by-step explanation:

Convert all units in cm

Let external diameter be $d_1$

Let internal diameter be $d_2$

Let height of pipe be "h"

$d_1\: = \: 2.4 \:cm$

$t_1 \: + \: t_2\: = \: (0.2\: + \: 0.2) \: cm$

$h \: = \: 700 \: cm$

Here thickness of cylinder is denoted by "t"

Now

$d_2\: = \: 2.4\: - \: ( 0.4 )$

$d_2\: = \: 2 \: cm$

Volume of hollow cylinder = $\pi h [(r_1)^{2} \: - \: (r_2)^{2}]$

For radius divide it by 2

$r_1 \: = \: 1.2\: cm$

$r_2 \: = \: 1 cm$

V = π (700)[(1.2×1.2) - ( 1×1)]

V = π (700) (0.44)

V = 22 × 100 × 0.44

V = 968 cm³

1 cu cm of lead is equal to 10 g

So

Total weight of lead = 968 × 10 g

So , weight of lead is 9680 g as per question.