Question

please answer please please please ... branliest answer will be marked...excuses will we reported​

Answer 1

Answer:

(b)

Hey, i have an idea put the options in place of a and b, if it gets zero then its the ans (as x value already given, x=1,3)

Answer 2

Step-by-step explanation:

9)a)

$x + \frac{7}{2} > \frac{5x}{3} + 3 \\ \frac{7}{2} - 3 > \frac{5x}{3} - x \\ \frac{7 - 6}{2} > \frac{5x - 3x}{3} \\ \frac{1}{2} > \frac{2x}{3} \\ x < \frac{3}{4} \: \: \: \: ans.$

9)b)

$let \: \: f(x) = ax {}^{3} - 3x {}^{2} + bx + 3 \\ (x - 1) \: \: so \: \: taking \: \: x = 1 \\ f(1) = a - 3 + b + 3 = 0 \: \: \: \: \: \: (a = - b) \: \: \: first \: \: equation\\ because \: \: (x - 1) \: \: is \: \: factor \: of \: \: function \: \: f(x) \\ now \: \: \: \: (x - 3) \: \: so \: \: \: taking \: \: x = 3 \\ f(3) = 27a - 27 + 3b + 3 = 0 \\ 27a - 27 - 3a + 3 = 0 \\ 24a - 24 = 0 \: \: \: \: so \: \: \: a = 1 \: \: \: and \: \: \: \: b = - 1 \: \: \: \: \: \: ans.$

Hope it will help you.