Question

Please answer please
tomorrow is my test please

In the adjoining figure, AB || QP , BC || RQ
and CA || PAR , angle AEQ = 110 degree and angle RPQ = 50 degree , find angle A , angle B , angle C , angle Q ,angle R​

Answer 1

Answer:

angle aed=70

angle A+D=angle AEQ

angle A+D+E=180

Answer 2

Answer:

From giv fig

First taking AEQ +AED=180( linear pair)

by this we get AED =70

then, AED=QEF=70( vertically opposite angles)

then..

HPG=GFC(alternate interior angles since both lines are parallel)

GFC=EFQ=50(vertically opposite angles)

now, angle sum property in triangle QEF

we get 70+50+ Q =180

Q=60

now angle sum property in triangle PQR

50+60+R =180

R=70

GPH=BIG=50(alternate interior angles since both lines are parallel)

BIG=RID=50(vertically opposite angles)

now angle sum property in triangle RID

we get 70+50+RDI=180

RDI =60

RDI =ADE =60( vertically opposite angles)

now angle sum property in triangle AED

we get 60+70+A=180

A=50

now,

HPG=GFC(alternate interior angles since both lines are parallel)

HPG=FGC=50( vertically opposite angles)

angle sum property in triangle GFC

50+50+c=180

C=80

angle sum property in triangle ABC,

we get A+B+C=180

50+80+B=180

B=50