Physics, asked by Sameeksha2901, 7 months ago

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Answered by BrainlyTwinklingstar
4

Given :

Magnitude of electric field intensity = 3 × 10³ N/C

Side of the square = 10cm = 0.1m

To find :

(a) The flux of this field through a square of 10 cm on a side whose plane is parallel to the yz plane.

(b) The flux through the same square if the normal to its plane makes a 60° angle with the x- axis.

Solution :

(a) The plane of square is parallel to the yz plane. So, angle between the plane and electric field is 0°

Flux through the plane is given by,

 \bf Flux(\phi) =  | \vec{E}| A \: cos \theta

where,

  • E denotes Electric field intensity
  • A denotes area of square

by substituting all the given values in the equation,

 \dashrightarrow \sf \phi =  | \vec{E}| A \: cos \theta

 \dashrightarrow \sf \phi =  3 \times  {10}^{3}  \times 0.01 \times cos  0^{ \degree}

 \dashrightarrow \sf \phi =  30 \: N m^2/C

Thus, the flux of this field through a square of 10 cm on a side whose plane is parallel to the yz plane is 30Nm²/C.

(b) Here, the plane makes an angle of 60° with the x-axis so, the angle between them will be 60°

Applying the same formula,

 \dashrightarrow \sf \phi =  | \vec{E}| A \: cos \theta

 \dashrightarrow \sf \phi =  3 \times  {10}^{3}  \times 0.01 \times cos 60^{ \degree}

 \dashrightarrow \sf \phi =  3  \times 10 \times  \dfrac{1}{2}

 \dashrightarrow \sf \phi =  30 \times  \dfrac{1}{2}

 \dashrightarrow \sf \phi =  15 \: N m^2/C

thus, the flux through the same square if the normal to its plane makes a 60° angle with the x- axis is 15Nm²/C.

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