please answer properly

Answers
Given :
Magnitude of electric field intensity = 3 × 10³ N/C
Side of the square = 10cm = 0.1m
To find :
(a) The flux of this field through a square of 10 cm on a side whose plane is parallel to the yz plane.
(b) The flux through the same square if the normal to its plane makes a 60° angle with the x- axis.
Solution :
(a) The plane of square is parallel to the yz plane. So, angle between the plane and electric field is 0°
Flux through the plane is given by,
where,
- E denotes Electric field intensity
- A denotes area of square
by substituting all the given values in the equation,
Thus, the flux of this field through a square of 10 cm on a side whose plane is parallel to the yz plane is 30Nm²/C.
(b) Here, the plane makes an angle of 60° with the x-axis so, the angle between them will be 60°
Applying the same formula,
thus, the flux through the same square if the normal to its plane makes a 60° angle with the x- axis is 15Nm²/C.