Please answer.....Q.1. H2 and N2 gas was heated in a closed vessel of capacity 1L till equilibrium is established.. When the concentration of H2 and N2 are 10mol each,, equilibrium 2mols NH3 was formed.. calculate equilibrium constant for the reaction???
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N2 + 3H2 ----> 2NH3
Initial moles 2 2 0
Equilibrium moles 2-\alpha 2-3\alpha 2\alpha
Since 0.5 mole of N2 has been used up therefore :
\alpha= 0.5 mole
Moles of NH3 = 1
Concentration of NH3 = moles/volume = 1/5 mol/l
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