please answer Q. 33
itz from coordinate geometry
class 10 ncert
please itz urgent
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Answer:
r=√1+9=√10 cm
We observe that mid point of BC (3,3) is ortho centre
Step-by-step explanation:
Slope of AB
mAB=(6-4)/(4-0)=2/4=1/2
L is ( 2,5)
LO ⊥AM
So mLO=-1/mAB=-1/(1/2)=-2
Mo passes through L(2,5)
So y=mx+c
5=-2*2+c
So c=5+4=9
So equation of LO is
y= -2x+9.........................(1)
**************
Similarly
Slope of BC
mBC=(2-4)/(6-0)=-2/6= -1/3
M is ( 3,3)
MO ⊥AM
So mMO=1/mBC=-1/(-1/3)= 3
Mo passes through M(3,3)
So y=mx+c
3=3*3+c
So c=3-9=-6
So equation of MO is
y=3x-6............(2)
From (1) and (2)
3x-6=-2x+9
5x=15, x=3
and y=3*3-6=9-6=3
Thus the coordinates of Ortho centre are (3,3)
Ortho radius=OA=√(4-3)²+(6-3)²
r=√1+9=√10 cm
We observe that mod point BC (3,3) is ortho centre
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