Question

please answer Q19...

Answer 1

relationship between momentum and kinetic energy is
K.E = P²/2m

P = √(2K.Em )

let initial kinetic energy is 100 j and mass is m
then,
P = √(200m) ----(1)

now,
increase K.E , by 100 %
new K.E = 200 j

now , P = √(400m) ------(2)

now,
change In P = {√(400m)-√(200m) }

% change in P = { √(400m) -√(200m)}/√(200m) × 100

= { √2 -1 } × 100

=( 1.414 -1)× 100

= 41.4 %

Answer 2

Answer:

relationship between momentum and

kinetic energy is K.E = P?/2m

P= v(2K.Em )

let initial kinetic energy is 100 j and mass then,

(2)

is m

P = v(200m) ----(1)

now,

increase K.E, by 100% new K.E = 200 j

now, Tv(400m)

now,

change In P = {V(400m)-v(200m) }

% change in P ={ v(400m) -v(200m)}/ V(200m) x 100

= { v2 -1} x 100

=( 1.414 - 1)* 100

= 41.4 %