Question

please answer Q3 ,Q4,Q8 , Q9,Q10 with explanation and rest direct answer
25 points!!!!

Answer 1

Q3 :- mole = wt/molar wt
wt of all are equal so,

mole ratio = 1/32 : 1/2 : 1/16
= 1 : 16 : 2

Q4 :- mole = given wt /molar wt
= 19.7 × 10³ /197 = 100

no of gold atoms = mole × 6.023 × 10²³
= 100 × 6.023×10²³
=6.023×10^25

Q5 :-
equivalent wt of H3PO2 = molar wt /n-factor = M/1
because H3PO2 is monobasic acid


Q8;-
no of atoms = mole of atoms × 6.023×10²³
mole of atom = 3 × mole of molecule
=0.3

so, no of atoms = 0.3×6.023 × 10²³ =1.8069 × 10²³


Q 9 :-
mass of Ca = 40℅ of 5 g
= 40× 5/100 = 2 g

Q10 :-
mole of sugar = 1.71/342 = 0.5× 10-³
no of mole of C = 12 × 0.5 × 10-³
= 6 × 10-³

no of carbon atoms = 6 × 6.023× 10²³
≈3.6 × 10²²

Answer 2

Q3:- mole = wt/molar wt wt of all are equal so,

mole ratio = 1/32 : 1/2 : 1/16

= 1:16:2

Q4 :- mole = given wt /molar wt = 19.7 x 103 /197 = 100

no of gold atoms = mole x 6.023 x 1023 = 100 x 6.023x1023 =6.023x10^25

Q5:

equivalent wt of H3PO2 = molar wt /n factor = M/1 because H3PO2 is monobasic acid

Q8;

Chemistry

21 points

no of atoms = mole of atoms x 6.023x1023 = mole of atom 3 x mole of molecule =0.3

so, no of atoms = 0.3x6.023 x 1023 =1.8069 x 1023

Q9:

mass of Ca = 40% of 5 g = = 40* 5/100 = 2 g

Q10 :

mole of sugar = 1.71/342 = 0.5x 10-3 = no of mole of C = 12 x 0.5 10-3 = 6 x 10-3

no of carbon atoms = 6 x 6.023× 1023 =3.6 x 1022