Question

please answer Q33..... it's urgent​

Answer 1

Answer:

Given, f(x) = px^2+5x+r  and factors are x-2, x-1/2

Substitute x = 2 in place of equation, we get

= p*2^2+5*2+r=0  

=  4p + 10 + r = 0   ------------  (i)

Substitute x = 1/2 in place of equation.  

= p/4 + 5/2 + r = 0

 = p + 10 + 4r = 0  -------------------  (ii)

On solving (i),(ii) we get

4p+r=-10 and p+4r+10=0

4p+r=p+4r

3p=3r   

p = r.

HOPE THAT IT WAS HELPFUL!!!!

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Answer 2

Answer:

2and 1/2 are factor f(2) and f(1/2) =0

px2+5x+r = a(x-2)(x-1/2)

=on solving

2ax^2-5ax+2a

on comparing

p=q=2a. where a is constant