please answer Q34....
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use formula,
n(A U BU C) = n(A) + n( B) + n( C) -n( AnB) - n( BnC) -n(CnA) + n( AnBnC)
here n(AUBUC) = total number of medals
n(A) =no of medals in football
n(B) = no of medals in basket ball
n(c) = no of medals in cricket
in the same way n(AnB) , n(BnC) , n(CnA)
are the no of medals in at least two game .
now,
58 = 38 + 15 + 20 -(n(AnB)+n(BnC)+n(CnA)} +3
58 = 58 + 18 -{n(AnB)+n(BnC)+n(CnA)}
n(AnB)+ n(BnC) + n(CnA) = 18 ( answer)
n(A U BU C) = n(A) + n( B) + n( C) -n( AnB) - n( BnC) -n(CnA) + n( AnBnC)
here n(AUBUC) = total number of medals
n(A) =no of medals in football
n(B) = no of medals in basket ball
n(c) = no of medals in cricket
in the same way n(AnB) , n(BnC) , n(CnA)
are the no of medals in at least two game .
now,
58 = 38 + 15 + 20 -(n(AnB)+n(BnC)+n(CnA)} +3
58 = 58 + 18 -{n(AnB)+n(BnC)+n(CnA)}
n(AnB)+ n(BnC) + n(CnA) = 18 ( answer)
abhi178:
see answer john . i hope you understand
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