please answer Que 6) ,7)
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6) 301,303.......497
497 = 301 + 2 n -2
n= 99, TOTAL 99 TERMS
SUM = 99/2 ( 2× 301 + 98×2)
= 99/2 ( 602 + 196)= 39501
7)410,420.....490
490 = 410 + 10n -10
n =9
last term= first term+ (n-1) ×common difference
sum = 9/2 ( 2×410 + 8 ×10)
= 9/2 ( 820 +80)
= 4050
497 = 301 + 2 n -2
n= 99, TOTAL 99 TERMS
SUM = 99/2 ( 2× 301 + 98×2)
= 99/2 ( 602 + 196)= 39501
7)410,420.....490
490 = 410 + 10n -10
n =9
last term= first term+ (n-1) ×common difference
sum = 9/2 ( 2×410 + 8 ×10)
= 9/2 ( 820 +80)
= 4050
Answered by
2
Question 6) 39501
Question 7) 8730
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