Math, asked by bhumikapatil, 1 year ago

please answer Que 6) ,7)

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Answered by Anonymous
2
6) 301,303.......497

497 = 301 + 2 n -2

n= 99, TOTAL 99 TERMS

SUM = 99/2 ( 2× 301 + 98×2)
= 99/2 ( 602 + 196)= 39501


7)410,420.....490

490 = 410 + 10n -10
n =9

last term= first term+ (n-1) ×common difference

sum = 9/2 ( 2×410 + 8 ×10)
= 9/2 ( 820 +80)
= 4050
Answered by twincity
2

Question 6)   39501

Question 7)    8730

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