Please answer que no 24
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ranaji01020004:
it's easy
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Let us assume numbers are x,y and z.
Now, as per the question
x+ y = z+5 ........(i)
x+z = y + 7 .........(ii) or, x-y = 7-z
y + z = x + 2 ........(iii) or, y- x = 2 - z
Now, By adding (i) and (ii),
2x = 12 , => x = 6
And, By adding (i) and (iii) ,
2y = 7 => y = 7/2
Now, By putting the values in equation (i),
We will get
6 + 7/2 = z + 5
=> 19/2 = z + 5
=> z = 9/2 .
Thus, Numbers will be 6, 7/2 and 9/2 .
Hope it will help.
Now, as per the question
x+ y = z+5 ........(i)
x+z = y + 7 .........(ii) or, x-y = 7-z
y + z = x + 2 ........(iii) or, y- x = 2 - z
Now, By adding (i) and (ii),
2x = 12 , => x = 6
And, By adding (i) and (iii) ,
2y = 7 => y = 7/2
Now, By putting the values in equation (i),
We will get
6 + 7/2 = z + 5
=> 19/2 = z + 5
=> z = 9/2 .
Thus, Numbers will be 6, 7/2 and 9/2 .
Hope it will help.
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