please answer ques no. 7
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➡ 3^2x + 1 ÷ 9 (9 = 3^2) = 27 (27 = 3^3)
➡ 3^2x + 1 ÷ 3^2 = 3^3
➡ 3^2x + 1 - 2 = 3^3
➡ 3^2x - 1 = 3^3
♣♣ AS THE BASES ARE EQUAL, POWERS MUST BE EQUAL ♣♣
➡ 2x - 1 = 3
➡ 2x = 3 + 1
➡ 2x = 4
➡ x = 4 / 2
➡ x = 2
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➡ HOPE IT HELPS
➡ MARK MY ANSWER BRAINLIEST
➡ HAVE A NICE DAY FRIEND
➡ IF ANY PROBLEMS, FOLLOW ME AND YOU CAN CLARIFY YOUR DOUBTS
............................................................................................................♣♣♣
➡ 3^2x + 1 ÷ 9 (9 = 3^2) = 27 (27 = 3^3)
➡ 3^2x + 1 ÷ 3^2 = 3^3
➡ 3^2x + 1 - 2 = 3^3
➡ 3^2x - 1 = 3^3
♣♣ AS THE BASES ARE EQUAL, POWERS MUST BE EQUAL ♣♣
➡ 2x - 1 = 3
➡ 2x = 3 + 1
➡ 2x = 4
➡ x = 4 / 2
➡ x = 2
............................................................................................................♣♣♣
➡ HOPE IT HELPS
➡ MARK MY ANSWER BRAINLIEST
➡ HAVE A NICE DAY FRIEND
➡ IF ANY PROBLEMS, FOLLOW ME AND YOU CAN CLARIFY YOUR DOUBTS
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