Math, asked by tripti7114, 5 months ago

Please answer question 1 (b)​

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Answered by SandeepAW
1

Answer:

1. b) P=₹62500.

T=2 years 6months=30 months (Because 2years=24 months + 6 months=30 months).

R=12%.

SI=PTR/100.

SI=62500×30×12/100.

SI=1875000×12/100.

SI=22500000/100.

SI=₹225000.

Sorry small mistake.

Compound Interest=SI-P.

Compound Interest=225000-62500.

Compound Interest=162500.

I think this is your answer.

Answered by shaikainter786
1

Answer:

Present value =₹ 62500

Interest rate =12% per annum

Time =2 years 6 months =(2+ 1/2) years =5/2 years

To find the amount we have the formula,

Amount (A)=P(1+(r/100))

n

where P is present value, r is rate of interest, n is time in years.

Now substituting the values in above formula we get,

∴A=62500(1+12/100)^5/2

⇒A=62500(1+3/25)^2 [1+(1/2×12)/100]

⇒A=62500(28/25)^2 [1+6/100]

⇒A=62500(28/25)^2 (106/100)

⇒A=625×784/625×106=784×106

⇒A=625×784/625×106=784×106

⇒A=₹ 83104

And Compound interest =A–P

=83104–62500=₹ 20604

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