Question

Please answer question 12

Answer 1

Answer:

$\frac{m - n }{m + n}$

Step-by-step explanation:

sec θ = $\frac{m + n }{2\sqrt{mn} }$ . Then cos θ = $\frac{2\sqrt{mn} }{m + n}$

we know sin² θ + cos² θ = 1

Hence, $\frac{4mn}{(m+n)^{2} }$ + sin² θ = 1

sin² θ = 1 - $\frac{4mn}{(m + n)^{2} }$

sin² θ = $\frac{(m + n)^{2}-4mn}{(m + n)^{2} }$ = $\frac{(m - n)^{2}}{(m + n)^{2}}$

Hence, sin θ =$\frac{m - n }{m + n}$

PLEASE MARK ME AS THE BRAINLIEST!!