Math, asked by SS07, 9 months ago

Please answer question 12 full

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Answered by kapildev783023
1

Answer:

(I) x^2+3√3x+6=0

x^2+2√3x+√3x+6=0

x(x+2√3) +√3(x+2√3) =0

(x+√3) (x+2√3) =0

(ii) 7√2x^2-10x-4√2=0

7√2x^2-14x+4x-4√2=0

7√2x(x-√2)+4(x-√2)=0

(7√2x+4)(x-√2)=0

(iii) 64a^3-27b^3-144a^2b+108ab^2

(4a)^3-(3b)^3-3*(4 a) ^2*3b-3*4a*(3b)^2

(4a-3b)^3

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