Question

please answer question 13 fast please​

Answer 1

Explanation:

Question:-

A stone is thrown in a vertically upward direction with a velocity of 5m/s. If the acceleration of the stone during its motion is 10m/s² in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?

Solution:-

Initial velocity (u) = 5m/s

Final velocity (v) = 0m/s

Acceleration (a) = -10m/s²

Here, acceleration is negative because , it is in opposite direction of the velocity of the stone. ( u is upwards and a is downwards)

Let the height attained be s

And the time taken be t

Using 2nd equation of motion:-

⇢ v² - u² = 2as

⇢ 0² - 5² = 2 × (-10) ×s

⇢ -25 = - 20s

⇢ s = $\dfrac{-25}{-20}$

⇢ s = 1.25m

∴ Height attained by the stone = 1.25m

Using 1st equation of motion:-

⇢ v = u + at

⇢ 0 = 5 + (-10) × t

⇢ 0 = 5 - 10t

⇢ 10t = 5

⇢ t = $\dfrac{5}{10}$ = 0.5sec

∴ Time taken to reach there = 0.5s