Question

please answer question 18 urgent​

Answer 1

Answer:

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Answer 2

Answer:

I. 6 ohm

II. 2A

III. 4V

Explanation:

R2, R3 are in parallel so 1/Rp

= 1/R2+1/R3

=1/3+1/6

=3/6

=1/2

So Rp=2 ohm

Now Rp and R1 are in series

So Rs

= Rp+R1

= 2+4

=6 ohm

So effective resistance in the circuit is 6 ohm

Total current

= V/R

=12/6A

=2A

Now R1 and effective resistance Rp are in series so the current is same

So potential difference across Rp

=2×2 V

=4V

Now R2 and R3 are in parallel connection so p.d is the same

So p.d across R2 is 4V