Question

Please answer question 25, 26 and 27 please!
I will surely mark as brainliest

Answer 1

(25): Given

u=5m/s

v=25m/s

t=10s

so,a=(v-u)/t

=(25m/s-5m/s)10s

=20m/s/10s

=2m/s^2

Now distance covered =ut+1/2at^2

=5m/s×10s +1/2×2m/s^2×10s^2

=50m+1m/s^2×100s^2

=50m+100m

=150m