Question

Please answer question 32

Answer 1

Answer:

17.14 minutes

Explanation:

Snail climbs 9 dm(decimetre) in one minute and slips 2 dm in alternate minute.

So, snail climbs 7 dm every 2 minutes. Which can also be written as that his speed is Speed=Distance/Time i.e. 7/2=3.5 dm/minute.

The pole is 6 meter i.e. 60 dm (1 m=10dm)

Time=Distance/Speed

Time=60/3.5

Time=17.14 minutes

Answer 2

17.14 minutes

Explanation:

In the given question, we have to find the time required by the snail to reach the top.

Given-

snail move 7 dm per minute slip 2 dm another minute

To find-

time to reach the top at the height of 60 dm. (1m = 10 dm)

Explanation:

1) Since the snail move at speed of 9 dm and then slip therefore total distance covered by him in 2 minutes is

9-2 = 7 dm

2) In 1 minute he will move $\frac{7}{2}$ i.e 3.5 dm.

3)  speed - 3.5 dm/min

    distance - 60 dm

     time- ?

4) Speed= $\frac{distance}{time}$

5)  time = $\frac{distance}{speed}$

6)  = $\frac{60}{3.5}$

7 ) = 17.14 minutes

Thus, 17.14 minutes is the correct answer.