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Putting values in the given eq^.
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Hi ,
sin B = 1/2
sin B = sin 30
Therefore ,
B = 30 -----( 1 )
according to the problem given,
LHS = 3(cos B ) - 4 Cos³ B
= - ( 4cos³ B - 3 cos B )
[ since cos 3x = 4cos³ x - 3 cos x ]
= - cos 3B
= - cos ( 3 × 30) from ( 1 )
= - cos 90
= 0
= RHS
I hope this help you
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