Math, asked by khushboo18, 1 year ago

please answer question 5 and 6



tomorrow is my math exam please please please please please please please give

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Answers

Answered by brunila
1
6.
 we have to divide 29 into two parts so,
  x + y = 29
x = 29-y
then
  x^2 + y^2 = 425
   (29 - y )^2 + y^2 = 425
  841 + y^2 + 58y + y^2 = 425
  2y^2 + 58y + 416 = 0
  y^2 + 29y + 208 = 0
  y^2 + 13y +16y + 208 = 0
  y(y+13) + 16(y+13) = 0
  (y+16)(y+13) = 0
y = -13 and y = -16
then,
x = 42 and x = 45
therefore there are two ways to divide 29 according to above circumstances
those are 29 = 42 - 13 and 45 - 16.

khushboo18: what do u want to say
brunila: actually one question should be answered only once so how can i answer that again so u again ask that 5 .question
khushboo18: no I now I don't want the answer of that
khushboo18: I want answer of other question
khushboo18: the question is
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khushboo18: hey what happened can't be able to answer
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khushboo18: I mark u brainlest
Answered by souravkumar31ow5zan
0
Solve this equation to get the solution. +ve root will be the answer
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