Please answer question 67 and 69
No spams!!
Attachments:
Answers
Answered by
0
Question 69.
Time taken to reach ground=5s
time taken to reach top=2.5s (as time of acent = time of decent)
average velocity=5m/s
distance travelled=2.5*5=12.5m
average speed= total distance/total time taken
=12.5 (up) +12.5 (during down) ÷ 5s
= 5 m/s
Time taken to reach ground=5s
time taken to reach top=2.5s (as time of acent = time of decent)
average velocity=5m/s
distance travelled=2.5*5=12.5m
average speed= total distance/total time taken
=12.5 (up) +12.5 (during down) ÷ 5s
= 5 m/s
amanbgs95:
hyy
Similar questions
English,
7 months ago
India Languages,
7 months ago
English,
7 months ago
Science,
1 year ago
Computer Science,
1 year ago