Question

please answer question 6b​

Answer 1

Given -

$\sf v_{initial} = 25 \: ms^{-1}$

$\sf v_{final} = 15 \: ms^{-1}$

$\sf t_{initial} = 3 \: s$

$\sf t_{final} = 4 \: s$

Solution -

Therefore,

acceleration,

$\sf a = \dfrac{v_{final} - v_{initial}}{t_{final} - t_{initial}}$

$\: \: \: \: \sf= \dfrac{15 - 25}{4 - 3}$

$\: \: \: \: \sf = \dfrac{ - 10}{1} m {s}^{ - 2}$

$\: \: \: \: \sf = - 10 \: m {s}^{ - 2}$

Answer -

Acceleration = -10 m/s²

i.e.: (retardation = 10 m/s²)

Answer 2

Answer:

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Explanation:

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