Question

Please answer question is in attachment
Answer is option A just need steps and explaination.

Answer 1

$\huge{\underline{\underline{SOLUTION:-}}}$

The three R's given in a straight line are in Parallel, therefore, the resistance of that part is

$\frac{1}{Rp}$  = $\frac{1}{R}$ + $\frac{1}{R}$ +$\frac{1}{R}$

= $\frac{3}{R}$

Hence the resistance of that part = $\frac{R}{3}$

Now, the  left out resistances R and R are connected in series with the parallel part.,

Hence the net resistance is

R + $\frac{R}{3}$ + R

Taking LCM as 3 we get

>> $\frac{3R + R + 3R}{3}$

>>$\frac{7R}{3}$

$\boxed{\textsf{Hence\:resistance\:between\:A\:and\:B\:is{\frac{7R}{3}}}}$

Which is OPTION A

Answer 2

the right answer is option a