Question

Please answer question no. 10 (a)

I have have exam ╥﹏╥​

Answer 1

ᴀɴsᴡᴇʀ :

$:\implies \sf{ {2x}^{2} +7xy + {8y}^{2} = 0}$

$:\implies \sf{ {ax}^{2} + 2hxy +{by}^{2} = 0}$

${ \:\: \: \: \:\:\boxed{\sf{a = 2 \: \: \: \:\: \:\:2h =1\: \: \:\: \:\:\: b = 3}}}$

$\: \:\: \: \:\: \:\:\: \: \: \:\: \:\: \:\: \:\:\:\:\:\sf{h =\huge{ \frac{7}{2} }}$

$\sf{\theta ={tan}^{ - 1} \huge| \frac{2 \sqrt{ {h}^{2} - ab}}{a + b} | }$

$:\implies \sf{ {tan}^{ - 1} \huge| \frac{2 \sqrt{ (\frac{1}{2})^{2} - 2 \times 3}}{2 + 3} | }$

$:\implies \sf{ {tan}^{ - 1}\huge{ | \frac{2 \sqrt{ \frac{14}{4} - 6}}{5} | }}$

$:\implies\sf{{tan}^{ - 1} \huge| \frac{ \frac{2 \sqrt{14 - 24}}{4} }{5} | }$

$:\implies \sf{{tan}^{ - 1} \huge{ | \frac{2 \times(\frac{5}{2})}{5} | }}$

$\sf{:\implies\theta = {tan}^{ - 1} \:\:7}$

$\huge \: \: \: \: \: \: \: \: \: \sf{\boxed{ \theta = \tan \: 45}}$

Answer 2

Answer:

no sis vo mara questions pa har bar galat words istamal karta ha

ma na us ka ans ma bhi bola to vo dekha hi nahi ha

samaj ma hi nahi aata uskoo

kya karuu ABB

mara 1 hi friend ha us ka to take care hadd SA zyada hona chahiye na sis